(3t-4)(2t^2-t-5)=

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Solution for (3t-4)(2t^2-t-5)= equation: 


Simplifying
(3t + -4)(2t2 + -1t + -5) = 0

Reorder the terms:
(-4 + 3t)(2t2 + -1t + -5) = 0

Reorder the terms:
(-4 + 3t)(-5 + -1t + 2t2) = 0

Multiply (-4 + 3t) * (-5 + -1t + 2t2)
(-4(-5 + -1t + 2t2) + 3t * (-5 + -1t + 2t2)) = 0
((-5 * -4 + -1t * -4 + 2t2 * -4) + 3t * (-5 + -1t + 2t2)) = 0
((20 + 4t + -8t2) + 3t * (-5 + -1t + 2t2)) = 0
(20 + 4t + -8t2 + (-5 * 3t + -1t * 3t + 2t2 * 3t)) = 0
(20 + 4t + -8t2 + (-15t + -3t2 + 6t3)) = 0

Reorder the terms:
(20 + 4t + -15t + -8t2 + -3t2 + 6t3) = 0

Combine like terms: 4t + -15t = -11t
(20 + -11t + -8t2 + -3t2 + 6t3) = 0

Combine like terms: -8t2 + -3t2 = -11t2
(20 + -11t + -11t2 + 6t3) = 0

Solving
20 + -11t + -11t2 + 6t3 = 0

Solving for variable 't'.

The solution to this equation could not be determined.

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